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Tie-breaking rules in AICCF championships

I have a query which I would like to post on our AICCF forum:

It is quite likely that several players may end up in "tied" total scores in AICCF 1508 championship, esp.at the top-5 levels. I would like to know the tie-breaking rules which will be employed since a "play-off" is unlikely in AICCF championships?
There are several systems available in chess tournaments these days such as Sum of progressive scores, SB system,Neustadtl system, Median system, etc.

To cite an instance, in the 8th correspondence chess championship, Jørn Sloth was declared winner based on his superior Neustadtl score.Refer the following cross-table:

1. Sloth X ½ ½ 1 ½ ½ 1 1 ½ 1 ½ 1 1 1 1 11 69.5
2. Zagorovsky ½ X 0 ½ 1 ½ 1 1 1 ½ 1 1 1 1 1 11 66.75
3. Kosenkov ½ 1 X ½ ½ ½ ½ ½ 1 1 ½ 1 1 1 1 10½ 67.5
4. Khasin 0 ½ ½ X ½ 1 ½ 0 1 1 ½ 1 ½ 1 ½ 8½ 54.75
5. Kletsel ½ 0 ½ ½ X ½ ½ ½ ½ 0 1 1 ½ 1 1 8 53.5
6. De Carbonnel ½ ½ ½ 0 ½ X ½ ½ 0 1 ½ ½ 0 1 1 7 45.25
7. Arnlind 0 0 ½ ½ ½ ½ X ½ 1 0 ½ ½ 1 1 ½ 7 42.5
8. Dunhaupt 0 0 ½ 1 ½ ½ ½ X 0 ½ 1 0 1 ½ 1 7 41.5
9. Maedler ½ 0 0 0 ½ 1 0 1 X 1 ½ ½ ½ ½ 1 7 41.5
10. Estrin 0 ½ 0 0 1 0 1 ½ 0 X 1 1 1 0 1 7 40.5
11. Walther ½ 0 ½ ½ 0 ½ ½ 0 ½ 0 X 0 1 ½ 1 5½ 33.25
12. Boey 0 0 0 0 0 ½ ½ 1 ½ 0 1 X ½ ½ 1 5½ 28.5
13. Abramov 0 0 0 ½ ½ 1 0 0 ½ 0 0 ½ X ½ 1 4½ 24.75
14. Siklos 0 0 0 0 0 0 0 ½ ½ 1 ½ ½ ½ X 1 4½ 22.75
15. Nun 0 0 0 ½ 0 0 ½ 0 0 0 0 0 0 0 X 1 7.75

In the above cross-table, the penultimate column shows the players' main scores, with their Neustadtl scores shown in the last column. As can be seen, both Jørn Sloth and Vladimir Zagorovsky finished with 11/14, but Sloth was declared Correspondence Chess World Champion because of his superior Neustadtl score.

The basic idea should be devise a method to see that the best player or the player who faced the stiffest competition or opposition to achieve the same number of tied points should be ranked higher.

I would invite comments from our enlightened AICCF members & arbiters of various CC & other tournaments.

Kind regards,
Anil

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Re: Tie-breaking rules in AICCF championships

In the startlist of T-1507, the first instruction read: The AICCF Tournament Rules shall apply. The games will be AICCF and ICCF rated. At the conclusion of the Championship, ties if any, will be resolved in the following order: (a) FIDE tie breaking system (b) Results of the tied players against each other (c) Player who has scored more wins (d) Players who scored more wins with Black pieces (e) Toss of coin.

In T-1508, this clause seems to have been omitted.

Re: Tie-breaking rules in AICCF championships

Thanks Dhanish for the info.
I hope Dr. Chatterjee can display the "Tie-breaker" rules at the Webserver guide link on the Welcome screen so that the rules are common for all Webserver tournaments.

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Re: Tie-breaking rules in AICCF championships

I was able to locate an earlier mail of Dr Chatterjee which says:
Anyway here is the relevant
extract from the announcement of the Sixth AICCF Championship from the
February 2003 Bulletin:

10. The AICCF Tournament Rules shall apply. The games will be AICCF
and ICCF rated. At the conclusion of the Championship, ties if any,
will be resolved in the following order: (a) New FIDE tie breaking
system (b) Results of the tied players against each other (c) Player
who has scored more wins (d) Players who scored more wins with Black
pieces (e) Toss of coin.

In case you are unfamiliar with "New FIDE tie breaking system, here is
the extract from the
Bulletin of August 2001 which talks about 1505 but the same rules
apply for 1506:

As mentioned in the announcement, the recently amended FIDE rules for
tie breaks in Round Robin Tournaments will be applied. Accordingly
ties in 1505 will be resolved by applying the following criteria:
(a) Direct Encounter: Sum of points from encounters amongst the tied players.
(b) Koya System: The number of points achieved against all opponents
who have scored 50% or more.
(c) Sonneborn-Berger (S.B.): The sum of points of the opponents
against whom the player has won, plus half the sum of points against
whom the player has drawn.
(d) Number of Won Games: The total number of games the player has won
in the entire tournament.

Interested persons may refer to the FIDE Handbook
(http://handbook.fide.com: FIDE Tournament Rules --> Annex to Rules).

It may be recalled that I had won T-1506 on tie break, but the current cross-table at http://www.aiccf-chess.com/server/cross_table.php?T=1506 mentions two winners?!

Re: Tie-breaking rules in AICCF championships

Shri Dhanish has correctly explained the tie breaking rules. However in 1508 he has now emerged a clear winner (without tie break).
Shri Dhanish writes:
"It may be recalled that I had won T-1506 on tie break, but the current cross-table at http://www.aiccf-chess.com/server/cross_table.php?T=1506 mentions two winners?!"
...This is because the server algorithm merely considers the highest points and does not apply any tie breaker rules.

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